Page 54 - Math Course 1 (Book 2)

Solving Linear Equations

Standardized Test Example
C: Substitute 4 for H.

Example 1 • 6H = 1 • 10(H – 2)
2
2
Find the value of H so that the f gures have the 1 • 6 • 4 ≟ 1 • 10(4 – 2)
same area. 2 2
A 1 B 3
C 4 D 5 12 ≟ 5 • 2

12 ≠ 10

D: Substitute 5 for H.
1 1
Read the Test Item • 6H = • 10(H – 2)
2 2
1 1
The equation • 6H = • 10 (H – 2)
2 2 1 1
• 6 • 5 ≟ • 10(5 – 2)
represents this situation. 2 2
15 ≟ 5 • 3
Solve the Test Item
15 = 15
You can solve the equation or substitute each value
into the equation and see if it makes the equation
true. We will solve by substitution.

Your Turn!
A: Substitute 1 for H.
1 1 No Solutions or Identity
• 6H = • 10(H – 2)
2 2 8a
Solve 2(4a + 8) = 3( – 10)
1 1 3
• 6 • 1 ≟ • 10(1 – 2) A. true for all values of a
2 2

3 ≟ 5 • –1 B. no solution

3 ≠ –5 C. 1
3
D. 2
B: Substitute 3 for H.
Answer
1 1
• 6H = • 10(H – 2)
2 2

1 1
• 6 • 3 ≟ • 10(3 – 2)
2 2
9 ≟ 5 • 1

9 ≠ –5

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