Page 83 - Math Course 1 (Book 2)
P. 83

Midpoints of a Segment





                                                                   Solve each equation
                             Let’s Begin
                                                                            X  + (–5)
                                                                     –6 =    1
                                                                               2
                                                                     –12 = X  – 5      Multiply each side by 2.
               Find Coordinates of Midpoint                                1
                                                                          –7= X        Add 5 to each side.
                                                                           1
                   Example                                                  y  + (–3)
                                                                      4 =    1
                                                                               2
                ALGEBRA                                                   8 = y  – 3   Multiply each side by 2.
                                                                          1
                The coordinates on a number line of J and K are         11 = y         Add 3 to each side.
                –12 and 16, respectively. Find the coordinate of the      1
                midpoint of JK
                                                                      Answer         The coordinates of D are
                Let M be the midpoint of JK                                                  (–7, 11).
                     –12 + 16
                M =                   a = –12, b = 16
                        2
                     4
                     =      or 2      Simplify.
                     2                                            Use Algebra to Find Measures

                    Answer                   2                       Example



                Find the coordinates of M, the midpoint of GH, for    What is the measure of PR if Q is the midpoint of
                G (8, –6) and H (–14, 12).
                                                                   PR?

                Let G be (X , Y ) and H be (X , Y ).
                          1  1           2  2
                       X  + X     y  + y
                   M (   1   2  ,  1  2  )
                          2         2
                       8 + (–14)    –6 + 12
                 = M (           ,           )                     You know that Q is the midpoint of PR, and the
                           2           2
                                                                   f gure gives algebraic measures for QR and PR.
                       –6     6
                 = M (      ,     ) or M (–3, 3)                   You are asked to f nd the measure of PR.
                        2     2

                                                                                                            1
                    Answer                (–3, 3)                  Because Q is the midpoint, you know that QR =    PR
                                                                                                            2

                Find the coordinates of D if E (–6, 4) is the midpoint   Use this equation and the algebraic measures to
                of DF and F has coordinates (–5, –3)
                                                                   f nd a value for x.

                Let F be ( x  y ) in the Midpoint Formula.              1
                          2  2                                     QR =      PR        Def nition of midpoint
                                                                        2
                             x +(–5)     y +(–3)     (X , Y )              1
                E(–6, 4) = E  1       ,   1            2   2       6 – 3x =       (14x + 2)  QR = 6 – 3x, PR = 14 + 2
                                                                           2
                                2          2       = (–5, –3)
                Write two equations to f nd the coordinates of D.  6 – 3x = 7x+1       Distributive Property

                        x + (–5)                 y + (–3)          5 – 3x = 7x         Subtract 1 from each side.
                  –6 =   2                 4 =    1
                           2                        2
                                                                             5 = 10x   Add 3x to each side.

                                                                        1
                                                                                 = x   Divide each side by 10.
                                                                        2
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