Page 97 - Math Course 3 (Book 2)
P. 97

Properties of Isosceles and Equilateral Triangles





                 MO. 9 - L6b                                      Name two congruent angles.

                     Properties of Equilateral                    By the converse of the Isosceles Triangle Theorem,

                                Triangles                         the sides opposite congruent angles are congruent.
                                                                  So, PL ≅ PM.           M

                COROLLARIES                                                   P


                 9.3 A triangle is equilateral if and only it it is
                        equiangular.
                                                                             L                        N


                                                                     Answer             PL and PM


                 9.4 Each angle of an equilateral triangle
                        measure 60°.
                                                                  Use Properties of Equilateral Triangles
                                       60°

                                                                    Examples

                                 60°        60°

                                                                   △EFG is equilateral, and EH bisects ∠FEG.
                                                                   EJ bisects ∠HEG. Find ∠HEJ and m∠EJH.

                             Let’s Begin                                                 E





               Congruent Segments and Angles

                  Examples                                                     F      H    J      G


                                                                   Each angle of an equilateral triangle measures 60°.
                Name two congruent angles.
                                                                   So, m∠FEH + m∠HEG = 60. Since the angle was
                ∠MLN is opposite MN and ∠MNL is opposite ML, so    bisected, m∠FEH = m∠HEG = 30. EJ bisects ∠HEG,
                ∠MLN ≅ ∠MNL.                                       so m∠HEJ = m∠JEG = 15.

                                       M
                                                                   ∠HEG is an exterior angle of ΔEGJ.
                           P
                                                                   m∠EJH = m∠GEJ + m∠EGJ     Exterior Angle
                                                                                             Theorem
                                                                                  = 60 + 15  Substitution

                           L                        N                             = 75       Add



                   Answer         ∠MLN and ∠MNL                       Answer       m∠HEJ = 15 ; m∠EJH = 75



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