Page 212 - Math Course 3 (Book 2)
P. 212

Probability of Compound Events




                                                           Dependent Events
          At the school carnival, winners in the ring-toss
          game are randomly given a prize from a bag that    A gumball machine contains 16 red gumballs,
          contains 4 sunglasses, 6 hairbrushes, and 5 key   10 blue gumballs, and 18 green gumballs. Once
          chains. Three prizes are randomly drawn from the   a gumball is removed from the machine, it is not
          bag and not replaced.                             replaced. Find each probability if the gumballs are
                                                            removed in the order indicated.
          Find P(hairbrush, hairbrush, key chain).
                                                            P(red, green, blue)
          The selection of the first prize affects the
          selection of the next prize since there is one    A.   45
          less prize from which to choose. So, the events      1331
          are dependent.
                                                            B.  120
          First Prize:                                         3311
                         6  ←number of hairbrush
                                                                195
          P(hairbrush) =  15  ←total number of prizes       C.  3311

          Second Prize:                                     D.   153
                        5  ←number of hairbrush                5324
          P(hairbrush) =
                        14  ←total number of prizes
                                                              Answer
          Third Prize:
                        5  ←number of key chains            P(green, blue, not red)
          P(key chain) =          ←total number of prizes
                       13
                                                            A.   45
                                                               1331
         P(hairbrush, hairbrush, key chain) =
         P(hairbrush) • P(hairbrush) • P( key chain)        B.  120
                                                               3311
              6            5             5
         =                     •                           •  Substitution  195
             15            14           13                  C.
            150      5                                         3311
         =              or   Multiply
           2730     91          Substitution
                                                            D.   153
                                                               5324
                          The probability of drawing
            Answer      hairbrush a hairbrush, and a key      Answer
                                         5
                                chain is          .
                                        91


         Your Turn!


        Independent Events

         Two cities, Fairfield and Madison, lie on different faults. There is a 60% chance that Fairfield will experience
         an earthquake by the year 2010 and a 40% chance that Madison will experience an earthquake by 2010.
         Find the probability that both cities will experience an earthquake by 2010.

         A. 60%
         B. 40%
         C. 24%
         D. 100%


           Answer


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