Page 216 - Math Course 3 (Book 2)
P. 216

Probability Distributions
          Mo. 12


           Lesson 8
                                                                         Let’s Begin




          KEY CONCEPTS:
                                                           Random Variable
          1. Use random variables to compute
               probability.                                   Example
          2. Use probability distributions to solve
               real-world problems.

                                                            The owner of a pet store asked customers how
                                                            many pets they owned. The results of this survey
         MO. 12 - L8a                                       are shown in the table.


              Probability Distributions                          Number of Pets  Number of Costumers
                                                                       0                 3
                                                                       1                 37
                                                                       2                 33
                     Vocabulary A-Z                                    3                 18

                     Let us learn some vocabulary                      4                 9

                                                            Find the probability that a randomly chosen
         random variable                                    customer has at most 2 pets.

         A random variable is a variable with a value that is
         the numerical outcome of a random event.           There are 3 + 37 + 33 or 73 outcomes in which a
                                                            customer owns at most 2 pets, and there are 100
                                                            survey results.

                                                                                       73
                                                                           P(X ≤ 2) =
                                                                                      100
                                                                           The probability that a randomly
                                                               Answer     chosen customer owns at most 2
         discrete random variable                                               pets is           or 73%.
                                                                                       73
         A discrete random variable has a finite number of                             100
         possible outcomes.                                 Find the probability that a randomly chosen
                                                            customer has 2 or 3 pets.
            Number of Pets                                  There are 33 + 18 or 51 outcomes in which a
                 0                                          customer owns 2 or 3 pets.
                 1
                 2                                                                       51
                 3                                                        P(2 ≤ X ≤ 3) =  100
                 4
                                                                           The probability that a randomly
          We can let the random variable X represent           Answer    chosen customer owns 2 or 3 pets
                                                                                     51
            the number of pets owned. Thus, X can                                  is         or 51%.
                                                                                     100
                     equal 0, 1, 2, 3, or 4.








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