Page 44 - Math Course 1 (Book 2)
P. 44

Linear Equations: Multiplication and Division

           Mo. 8

           Lesson 3





          KEY CONCEPTS:
          1. Solve equations by using multiplication.
          2. Solve equations by using division                           Let’s Begin



                                                           Solve Using Multiplication by a Positive Number

         MO. 8 - L3a
                                                              Example
                   Solving Equations:
                                                                   s
                      Multiplication                         Solve        = 3. Check your solution.
                                                                   12

                                                                 s
          Key Concept                                           12  = 3       Original equation



                                                                              Multiply each side by 12.
         Multiplication Property of Equality

         Words      If an equation is true and each side
                    is multiplied by the same number, the
                    resulting equation is true.                Answer            and


         Symbols For any numbers a, b, and c, if a = b,
                    then ac = bc.
                                                           Solve Using Multiplication by a Fraction
         Examples        6 = 6             9 = 9
                      6 x 2 = 6 x 2    9x(–3) = 9x(–3)       Examples
                        12 = 12          –27 = –27


                                 1        1                             3    2
                            10 x    = 10 x                    Solve –1    k =
                                 2        2                             8    3

                                                                                  Original Equation
         Solve –75 = –15b.
                                                                                  Rewrite the mixed number
              –75 = –15b       Original equation                                  as an improper fraction.
                                                                                                       8
                                                                                  Multiply each side by –
                                                     1                                             11  11
           1         1         Multiply each side by –                            the  reciprocal of –
        –      (–75) =–      (–15b)                  15                                            8
          15         15        the reciprocal of –15

             Answer      5 = b      Check this result.         Answer                             check this result


                                                                           16
         To check that 5 is the solution, substitute 5 for b in   To check that –         is  the solution, substitute
         the original equation.                               16           33
                                                             –         for k in the original equation.
                                                              33


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