Page 127 - Math Course 3 (Book 2)
P. 127

Similarity of Triangles





                 Since AB || DC, ∠BAC ≅ ∠DCE by the Alternate      Now find RQ and QT.
                 Interior Angles Theorem.                          RQ = x + 3           QT = 2x + 10
                                                                         = 5 + 3 or 8           = 2(5) + 10 or 20
                 Vertical angles are congruent, so ∠BAE ≅ ∠DEC.


                               Therefore, by the AA Similarity
                   Answer                                            Answer             RQ = 8; QT = 20
                                 Theorem, ΔABE ~ ΔCDE.




               Parts of Similar Triangles                         Indirect Measurement

                   Example                                           Example




                ALGEBRA                                            INDIRECT MEASUREMENT
                                                                   Josh wanted to measure the height of the Sears
                Given RS || UT, RS = 4, RQ = x + 3, QT = 2x + 10,
                                                                   Tower in Chicago. He used a 12-foot light pole and
                UT = 10, find RQ and QT.                           measured its shadow at 1 P.M. The length of the
                                                                   shadow was 2 feet. Then he measured the length
                                                                   of the Sears Tower’s shadow and it was 242 feet at
                                                    R              that time. What is the height of the Sears Tower?

                                             x + 3     4

                                                       S
                                                Q                          drawing
                                                                            not to
                      U                                                     scale
                                                                                           x ft
                                          2x + 10


                      10                                                        12ft

                            T                                              2ft
                                                                                  242 ft
                Since RS || UT, ∠SRQ ≅ ∠UTQ and ∠RSQ ≅ ∠TUQ
                because they are alternate interior angles. By AA   Since the sun’s rays form similar triangles, the
                Similarity, ΔRSQ ~ ΔTUQ. Using the definition of   following proportion can be written.
                similar polygons,   RS  =  RQ
                                 TU     TQ                          height of Sear’s Tower (ft)  =  height of the light pole (ft)
                                                                  Sear’s Tower shadow length(ft)  light pole shadow length (ft)
                     RS      RQ                                    Now substitute the known values and let x be the
                     TU   =  TQ                                    height of the Sears Tower.
                      4   =    x + 3    Substitution                 x      12
                     10       2x + 10                               242  =  2      Substitution
                4(2x + 10) = 10(x + 3)  Cross products                 x • 2 = 242(12) Cross products

                     8x + 40 = 10x + 30  Distributive Property            2x = 2904  Simplify.
                                        Subtract 8x and 30 from             x = 1452  Divide each side by 2.
                             10 = 2x
                                        each side.                                The Sears Tower is 1452 feet
                                                                      Answer
                               5 = x    Divide each side by 2.                                tall.

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